operator overload

 Input Format

The overloaded operator + should receive two complex numbers ( and ) as parameters. It must return a single complex number.

The overloaded operator << should add "" to the stream where  is the real part and  is the imaginary part of the complex number which is then passed as a parameter to the overloaded operator.

Output Format

As per the problem statement, for the output, print "" followed by a newline where  and .

Sample Input

3+i4
5+i6

Sample Output

8+i10

Explanation

Given output after performing required operations (overloading + operator) is 8+i10.

Answer:

//Operator Overloading

#include<iostream>

using namespace std;

class Complex

{

public:

    int a,b;

    void input(string s)

    {

        int v1=0;

        int i=0;

        while(s[i]!='+')

        {

            v1=v1*10+s[i]-'0';

            i++;

        }

        while(s[i]==' ' || s[i]=='+'||s[i]=='i')

        {

            i++;

        }

        int v2=0;

        while(i<s.length())

        {

            v2=v2*10+s[i]-'0';

            i++;

        }

        a=v1;

        b=v2;

    }

};

///////////////////////////////////////////////////////

Complex operator + (Complex& obj1, Complex& obj2){

  Complex t ;

     t.a = obj1.a + obj2.a;

     t.b = obj1.b + obj2.b;

     return t;

}

ostream& operator <<(ostream& out , const Complex& obj){

    out<<obj.a<<"+i"<<obj.b<<endl;

    return out;

}

/////////////////////////////////////////////////////code done

//Overload operators + and << for the class complex

//+ should add two complex numbers as (a+ib) + (c+id) = (a+c) + i(b+d)

//<< should print a complex number in the format "a+ib"

int main()

{

    Complex x,y;

    string s1,s2;

    cin>>s1;

    cin>>s2;

    x.input(s1);

    y.input(s2);

    Complex z=x+y;

    cout<<z<<endl;

}